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Question

Photon A has twice the energy of photon B. Then which option is correct?

A
Momentum of A is less than momentum of B.
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B
Wavelength of A is less than wavelength of B.
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C
Wavelength of A is equal to wavelength of B.
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D
Wavelength of A is greater than wavelength of B.
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Solution

The correct option is B Wavelength of A is less than wavelength of B.
Energy of a photon E=hν
and momentum of photon p=hλ
E=pλν=pc

Given, EA=2EB and c is a constant.
pA=2pB
Now, λ1p
1λA=2λB
λA=λB2

So option B is correct.

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