Question

Photon and electron are given energy $\left({10}^{-2}J\right).$ Wavelengths associated with photon and electeon are ${\lambda }_{ph}$ and ${\lambda }_{el},$ then correct statement will be

• A. ${\lambda }_{ph}>{\lambda }_{el}$
• B. ${\lambda }_{ph}<{\lambda }_{el}$
• C. ${\lambda }_{ph}={\lambda }_{el}$
• D. $\frac{{\lambda }_{el}}{{\lambda }_{ph}}=c$

Answer 1

Answer: (A)

${\lambda }_{ph}>{\lambda }_{el}$

The wavelength of the photon will be greater than that of the electron because the mass of a photon is less than that of an electron.

$\Rightarrow {\lambda }_{ph}>{\lambda }_{e}l$