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I vs V - Varying Frequency

Photons of en...

Question

Photons of energy $5 eV$ are incident on the cathode, as shown in the figure. Electrons reaching the anode have kinetic energy varying from $6 eV$ to $8 eV$ . Find the work function of metal in $eV$ .

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Solution

The electrons emitted from cathode get accelerated by $5 V$ battery connected.

So, the kinetic energy of electrons reaching the anode will have two kinetic energies, one due to photoelectric effect and the other due to energy supplied by the battery.

$∴ K E = K E_{max} + e V = 8 [∵ KE due to photoelectric effect is taken to be maximum]$

$\Rightarrow h f - ϕ_{o} + e V = 8$

$\Rightarrow 5 - ϕ_{o} + 5 = 8$

$\Rightarrow ϕ_{o} = 2 eV$

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