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Question

Photons with energy 5 eV are incident on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A, if the stopping potential of A relative to C is

A
1 V
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B
3 V
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C
+3 V
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D
+4 V
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Solution

The correct option is B 3 V
When 5eV is incident the kinetic energy is 2eV it simply means the work function is W=5eV2eV=3eV

Similarly When 6eV is incident the kinetic energy should be 6eVW=6eV3eV=3eV
it simply means to stop them we need a negative potential at anode equal to 3eVe=3V
So answer is 3V i.e. option B is correct.

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