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Question
Photons with energy 5 eV are incident on a cathode C, on a photoelectric cell. The maximum energy of the emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A if the stopping potential of A relative to C is
Photons with energy 5 eV are incident on a cathode C, on a photoelectric cell. The maximum energy of the emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A if the stopping potential of A relative to C is
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Solution
The correct option is B −3 V
When 5 eV is incident and the kinetic energy is 2 eV it simply means the work function is W=5 eV−2 eV=3 eV
Similarly when 6 eV is incident the kinetic energy should be,
6 eV−W=6 eV−3 eV=3 eV
It simply means to stop them we need a negative potential at anode equal to 3eVe=3 V
so, answer is −3 V
When 5 eV is incident and the kinetic energy is 2 eV it simply means the work function is W=5 eV−2 eV=3 eV
Similarly when 6 eV is incident the kinetic energy should be,
6 eV−W=6 eV−3 eV=3 eV
It simply means to stop them we need a negative potential at anode equal to 3eVe=3 V
so, answer is −3 V
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