Pick out the solution from the values given in the brackets against each equation:
$y + 3 = 1 (4, - 2, 2)$

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Solution

The equation:-
$y + 3 = 1$
When,
$y = 4, L H S : 4 + 3 = 7 R H S : 1 L H S \neq R H S$
When ,
$y = - 2, L H S : - 2 + 3 = 1 R H S : 1 L H S = R H S$
When,
$y = 2, L H S : 2 + 3 = 5 R H S : 1 L H S \neq R H S$
Hence, $y = - 2$ satisfies the equation.

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