Question

Pick the solution from the values given in the brackets against each equation :

$3y-2=13,\left(4,2,5\right)$

Answer 1

Substituting , $y=4,$we get ,

$$\begin{gathered} 3y-2=3\times 4-2 \\ =12-2 \\ =10 \end{gathered}$$

Since , $10\ne 13$

So , $4$is not the solution of given equation.

Substituting , $y=2,$we get ,

$$\begin{gathered} 3y-2=3\times 2-2 \\ =6-2 \\ =4 \end{gathered}$$

Since , $4\ne 13$

So , $2$is not the solution of given equation.

Substituting , $y=5,$we get ,

$$\begin{gathered} 3y-2=3\times 5-2 \\ =15-2 \\ =13 \end{gathered}$$

Since , $13=13$

So , $5$is the solution of given equation.

We can say that $5$ is the solution of given equation.