$p K_{a}$ and $K_{a}$ of an acid are connected by the relation ---------

p k_{a}

l o g k_{a}

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p k_{a}

- p H

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p k_{a}

- l o g k_{a}

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p k_{a}

- l o g k_{b}

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Solution

The correct option is D $p k_{a}$ = $- l o g k_{a}$
$p K_{a}$ is an index to express the acidity of weak acids. $p K_{a}$ tells us how acidic (or not) a given hydrogen atom in a molecule is. The acidity
constant $K_{a} = \frac{[H_{3} O^{+}] [A^{-}]}{[A H]}$
This is also expressed in logarithmic form are follows:
$p K_{a} = - l o g_{10} (K_{a})$

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