pKa of weak acid is 3.0 . Effective range of a buffer of HA and A− is :
A
3 to 4
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B
4 to 6
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C
2 to 3
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D
2 to 4
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Solution
The correct option is D 2 to 4 Range of Buffer solution is [(pKa−1),(pKa+1)].
As pKa=3
So, pKa−1=3−1=2
and pKa+1=3+1=4 ∴ effective range of a buffer HA and A− is [2,4] i.e., from 2 to 4.