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Question

pKa of weak acid is 3.0 . Effective range of a buffer of HA and A is :

A
3 to 4
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B
4 to 6
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C
2 to 3
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D
2 to 4
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Solution

The correct option is D 2 to 4
Range of Buffer solution is [(pKa1),(pKa+1)].
As pKa=3
So, pKa1=31=2
and pKa+1=3+1=4
effective range of a buffer HA and A is [2,4] i.e., from 2 to 4.

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