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Theorem 2: Perpendicular from the Center to a Chord Bisects the Chord

Points P and ...

Question

Points P and Q are on line PS, But not seg RS
Point Q is a point of ray RS but not of ray SR
Point P is a point of ray SR, but not of ray RS.
Draw the figure.

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Solution

The figure given below describes the given points:

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Similar questions

Consider the following figure of line. Say whether following statements are true or false in context of the given figure.

(a) Q, M, O, N, P are points on the line.

(b) M, O, N are points on a line segment.

(c) M and N are end points of line segment.

(d) O and N are end points of line segment.

(e) M is one of the end points of line segment.

(f) M is point on ray.

(g) Ray is different from ray.

(h) Ray is same as ray.

(i) Ray is not opposite to ray.

(j) O is not an initial point of.

(k) N is the initial point of and.

Q. Consider the line

\overset{\leftrightarrow}{P Q}

given below and find whether the given statements are true or false:
(i) M Is a point on ray

\vec{N Q}

.
(ii) L is a point on ray

\vec{M P}

\vec{M Q}

is different from ray

\vec{N Q}

.
(iv) L, M, N are points on line segment

\bar{L N}

\vec{L P}

is different from ray

\vec{L Q}

Q. In the given figure, seg PT is the bisector of

∠

QPR. A line through R intersects ray QP at point S. Prove that PS = PR

Q. Draw diagrams illustrating each of the following situation:
(a) Three straight lines which do not pass through a fixed point.
(b) A point and rays emanating from that point such that the angle between any two adjacent rays is an acute angle.
(c) Two angles which are not adjacent angles, but still supplementary.
(d) Three points in the plane which are equidistant from each other.

Q. In the given figure, ray PQ touches the circle at point Q. PQ = 12, PR = 8, find PS and RS.

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Theorem 2: Perpendicular from the Center to a Chord Bisects the Chord

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