Polyethylene is obtained from calcium carbide. CaC2+2H2O⟶Ca(OH)2+C2H2 C2H2+H2⟶C2H4 nC2H4⟶(−CH2−CH2−)n Therefore, the amount of polyethylene obtained for 64 kg CaC2 is:
A
7 kg
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B
14 kg
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C
21 kg
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D
28 kg
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Solution
The correct option is C 28 kg CaC2+2H2O⟶Ca(OH)2+C2H2,
64 kg CaC2 = 1000 mol ( ∵ 64 is molecular wt. of CaC2)
Here 1000 mol of CaC2 gives 1000 mol of acetylene and it gives 1000 mol of ethylene. All of this ethylene is used to make polyethylene.
Somol=Wt.MolecularWt.
1000=Wt.28
Wt.=28×1000
Wt.=28kg
Therefore, the amount of polyethylene obtained for 64 kg CaC2 is 28kg.