Question

Position of a particle moving in $x-y$ plane as function of time t $2ti+4t^{2}j$. Equation of trajectory of the particle is

• A. $y=x^2$
• B. $y=2x$
• C. $y^2=x$
• D. $y=x$

Answer 1

The correct option is A $y=x^2$

From the question,

$x=2t\to t=\frac{x}{2}$

and $y=4t^2$

Put the value of $tiny$ we get

$y=4(\frac{x}{2}{)}^2$

$y=x^2$

The correct option is A.