Question

position of a particle moving in x-y plane as function of time t is $2\widehat{ti}+4t^2\hat{j}$. equation of trajectory of the particle is

• A. $y=x^2$
• B. $y=2x$
• C. $y^2=x$
• D. y=x

Answer 1

The correct option is A $y=x^2$

$x=2t\Rightarrow t=\frac{x}{2}$

$y=4t^2$

put $t=\frac{x}{2}$ we get $y=4\times \frac{x^2}{4}$

$y=x^2$