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Byju's Answer
Standard XII
Mathematics
Applications of Cross Product
Position vect...
Question
Position vectors of A, B, C are given by
→
a
,
→
b
,
→
c
where
→
a
×
→
b
+
→
b
×
→
c
+
→
c
×
→
a
=
0
. If
→
A
C
=
2
^
i
−
3
^
j
+
6
^
k
find
→
B
C
if BC
=
14
.
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Solution
Position vector of A, B,C are
¯
¯
¯
a
,
¯
¯
b
,
¯
¯
c
r
e
s
p
e
c
t
i
v
e
l
y
Given
¯
¯
¯
a
×
¯
¯
b
+
¯
¯
b
×
¯
¯
c
+
¯
¯
c
×
¯
¯
¯
a
=
0
A
,
B
,
C
a
r
e
c
o
l
l
i
n
e
a
r
−
−
→
B
C
×
−
−
→
A
C
a
r
e
c
o
l
l
i
n
e
a
r
/
p
a
r
a
l
l
e
l
−
−
→
B
C
=
t
−
−
→
A
C
∣
∣
∣
−
−
→
B
C
∣
∣
∣
=
|
t
|
∣
∣
∣
−
−
→
A
C
∣
∣
∣
14
=
|
t
|
>
|
t
|
=
2
t
=
±
2
−
−
→
B
C
=
±
2
(
2
ˆ
i
−
3
ˆ
j
+
6
ˆ
k
)
Suggest Corrections
0
Similar questions
Q.
If
→
a
+
→
b
+
→
c
=
0
, the prove that:
→
a
×
→
b
=
→
b
×
→
c
=
→
c
×
→
a
where
→
a
,
→
b
,
→
c
are non-zero vectors.
Q.
If
→
a
,
→
b
,
→
c
are positive vectors of vertices
A
,
B
,
C
of
Δ
A
B
C
. If
→
r
is position vector of a point
P
such that
(
|
→
b
−
→
c
|
+
|
→
c
−
→
a
|
+
|
→
a
−
→
b
|
)
→
r
=
|
→
b
−
→
c
|
→
a
+
|
→
c
−
→
a
|
→
b
+
∣
∣
→
a
−
→
b
∣
∣
→
c
then the point
P
always
Q.
If
[
→
a
→
b
→
c
]
=
→
k
, where
k
≠
0
, then
[
(
→
b
×
→
c
)
×
(
→
c
×
→
a
)
(
→
c
×
→
a
)
×
(
→
a
×
→
b
)
(
→
a
×
→
b
)
×
(
→
b
×
→
c
)
]
=
Q.
Prove that points
A
,
B
,
C
having positions vectors
→
a
,
→
b
,
→
c
are collinear, if
[
→
b
×
→
c
+
→
c
×
→
a
+
→
a
×
→
b
]
=
→
0
Q.
If
→
a
,
→
b
,
→
c
are three vectors such that
→
a
×
→
b
=
→
c
,
→
b
×
→
c
=
→
a
,
→
c
×
→
a
=
→
b
then prove that
|
→
a
|
=
|
→
b
|
=
|
→
c
|
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