wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Position vectors of A, B, C are given by a,b,c where a×b+b×c+c×a=0. If AC=2^i3^j+6^k find BC if BC=14.

Open in App
Solution

Position vector of A, B,C are ¯¯¯a,¯¯b,¯¯crespectively
Given
¯¯¯aׯ¯b+¯¯bׯ¯c+¯¯cׯ¯¯a=0A,B,CarecollinearBC×ACarecollinear/parallelBC=tACBC=|t|AC14=|t|>|t|=2t=±2BC=±2(2ˆi3ˆj+6ˆk)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Applications of Cross Product
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon