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Question

Position vectors of A, B, C are given by a,b,c where a×b+b×c+c×a=0. If AC=2^i3^j+6^k find BC if BC=14.

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Solution

Position vector of A, B,C are ¯¯¯a,¯¯b,¯¯crespectively
Given
¯¯¯aׯ¯b+¯¯bׯ¯c+¯¯cׯ¯¯a=0A,B,CarecollinearBC×ACarecollinear/parallelBC=tACBC=|t|AC14=|t|>|t|=2t=±2BC=±2(2ˆi3ˆj+6ˆk)

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