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Types of Redox Reactions

Potassium aci...

Question

Potassium acid oxalate $K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} .4 H_{2} O$ can be oxidized by $K M n O_{4}$ in acidic medium. Calculate the volume (in ml) of 0.1 M $K M n O_{4}$ reacting in acidic solution with 1.27 gram of the acid oxalate.

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Solution

Molar mass of acid oxalate $K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} .4 H_{2} O = 508 g / m o l$
So, mmols of acid oxalate $= \frac{1.27}{508} \times 1000 = 2.5 m m o l$
So, meqv of acid oxalate = 2.5 × 8 = 20 meqv (n-fac of potassium acid oxalate = 8)
Since potassium acid oxalate can be oxidised by $K M n O_{4}$ , so
$20 = V \times 0.1 \times 5$
$\Rightarrow V = 40 m l$ (n-factor of $K M n O_{4} = 5$ )

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