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Standard XII

Chemistry

Reactivity Towards Halogens

Potassium at ...

Question

Potassium (at No.19) and chlorine (at No.17) form a compound. Explain the formation of the compound on the basis of
(a) oxidation.

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Solution

2K + $C l_{2}$ → 2KCl

Oxidation - In the electronic concept, oxidation is a process in which an atom or ion loses electron(s).

K → $K^{+}$ + $e^{-}$
Since potassium loses electrons to form $K^{+}$ in KCl, it undergoes oxidation.

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Reactivity Towards Halogens

Standard XII Chemistry

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Potassium (at No.19) and chlorine (at No.17) form a compound. Explain the formation of the compound on the basis of (a) oxidation.

2K + Cl2→ 2KCl Oxidation - In the electronic concept, oxidation is a process in which an atom or ion loses electron(s). K → K+ + e− Since potassium loses electrons to form K+ in KCl, it undergoes oxidation.

Potassium (at No.19) and chlorine (at No.17) form a compound. Explain the formation of the compound on the basis of
(a) oxidation.

2K + $C l_{2}$ → 2KCl

Oxidation - In the electronic concept, oxidation is a process in which an atom or ion loses electron(s).

K → $K^{+}$ + $e^{-}$
Since potassium loses electrons to form $K^{+}$ in KCl, it undergoes oxidation.