Question

Potassium (at No.19) and chlorine (at No.17) form a compound. Explain the formation of the compound on the basis of ​ ​

(d) reducing agent

Answer 1

(d) $2K+C{l}_2\to 2KCl$

A reducing agent is one that reduces other substances either by providing electrons or by providing hydrogen or an electropositive ion, or by removing oxygen or an electronegative ion.

$K\to K^{+}+e^{-}$

Potassium provides electrons to form ${Cl}^{-}$in $KCl$ and hence potassium acts as a reducing agent and gets oxidized.