Question

Potassium peroxochromate $K_{3}Cr{O}_8$ is a red-brown paramagnetic solid prepared from the following reaction.
$Cr{O}_4^{2-}+H_2{O}_2+O{H}^{-}\to [Cr{O}_8{]}^{3-}+H_{2}O+O_2$
If oxidation state of $Cr$ in product is $X$, number of peroxide bonded $O$ in product is $Y$ and number of electrons in d orbital of $Cr$ is $Z$ then what is value of $X+Y+Z$?

• A. 14.0
• B. 14
• C. 14.00

Answer 1

Answer: (A), (B), (C)

Since all the oxygens present are peroxide bonded, the
oxidation state of $Cr$ is, $\left(X\right)$ = $5$.
Total number of peroxide bonded $O$ are, $\left(Y\right)$ = $8$.
Number of electrons in $d$ orbitals of $Cr$ is, $\left(Z\right)$ = $1$.
So $X+Y+Z=14$