Potassium peroxochromate K3CrO8 is a red-brown paramagnetic solid prepared from the following reaction- CrO2-4 - H2O2 - OH- - -CrO8-3- - H2O - O2 If oxidation state of Cr in product is X- number of peroxide bonded O in product is Y and number of electrons in d orbital of Cr is Z then what is value of X - Y - Z-

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Standard XII

Chemistry

Potassium Dichromate

Potassium per...

Question

Potassium peroxochromate $K_{3} C r O_{8}$ is a red-brown paramagnetic solid prepared from the following reaction.
$C r O_{4}^{2 -} + H_{2} O_{2} + O H^{-} \to [C r O_{8}]^{3 -} + H_{2} O + O_{2}$
If oxidation state of $C r$ in product is $X$ , number of peroxide bonded $O$ in product is $Y$ and number of electrons in d orbital of $C r$ is $Z$ then what is value of $X + Y + Z$ ?

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Solution

Since all the oxygens present are peroxide bonded, the
oxidation state of $C r$ is, $(X)$ = $5$ .
Total number of peroxide bonded $O$ are, $(Y)$ = $8$ .
Number of electrons in $d$ orbitals of $C r$ is, $(Z)$ = $1$ .
So $X + Y + Z = 14$

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Since all the oxygens present are peroxide bonded, the oxidation state of Cr is, (X) = 5. Total number of peroxide bonded O are, (Y) = 8. Number of electrons in d orbitals of Cr is, (Z) = 1. So X+Y+Z=14

Since all the oxygens present are peroxide bonded, the
oxidation state of $C r$ is, $(X)$ = $5$ .
Total number of peroxide bonded $O$ are, $(Y)$ = $8$ .
Number of electrons in $d$ orbitals of $C r$ is, $(Z)$ = $1$ .
So $X + Y + Z = 14$