Potassium when heated strongly in oxygen, it forms:

K_{2} O

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K O_{2}

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K_{2} O_{2}

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K O_{3}

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Solution

The correct option is B $K O_{2}$
When potassium is heated with oxygen, it forms potassium superoxide.
$K + O_{2} - \to Δ K O_{2}$

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Similar questions

Q. Oxidation number of potassium in

K_{2} O, K_{2} O_{2}, K O_{2}

respectively, are :

Potassium when heated strongly in oxygen forms:

Q.
The oxidation number of oxygen in

K_{2} O, K_{2} O_{2}

and

K O_{2}

are respecitvely :

The stability of $K_{2} O$ , $K_{2} O_{2}$ and $K O_{2}$ is in order $K_{2} O < K_{2} O_{2} < K O_{2}$ . The increasing stability at the size of metal ion increases is due to stabilization of:

Q. Oxidation number of potassium in

K_{2} O

K_{2} O_{2}

and

K O_{2}

, respectively, is:

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Potassium when heated strongly in oxygen, it forms:

The correct option is B KO2When potassium is heated with oxygen, it forms potassium superoxide.K+O2−→ΔKO2

The correct option is B $K O_{2}$
When potassium is heated with oxygen, it forms potassium superoxide.
$K + O_{2} - \to Δ K O_{2}$