potential energy of particles varies with distance x as u= arootx / x^2 +b^2 where a and b are dimensional constants then dimensional formula a?b is??

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$A s b^{2} i s s u b t r a c t e d f r o m x^{2} T h e d i m e n t i o n a l f o r m u l a o f x^{2} w i l l b e e q u a l t o t h a t o f b^{2} b = L^{2} T h e d i m e n t i o n s o f \frac{a \sqrt{x}}{x^{2}} i s e q u a l t o t h a t o f U t h a t i s M^{1} L^{2} T^{- 2} a = M^{1} L^{\frac{7}{2}} T^{- 2} R E G A R D S$

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potential energy of particles varies with distance x as u= arootx / x^2 +b^2 where a and b are dimensional constants then dimensional formula a?b is??

Dear Student As b2 is subtracted from x2The dimentional formula of x2 will be equal to that of b2b=L2The dimentions of axx2 is equal to that of U that is M1L2T-2a=M1L72T-2REGARDS