Potential in the x-y plane is given as $V = 5 (x^{2} + x y)$ volts. The electric field at the point $(1, - 2)$ will be

3^j V/m

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- 5^j V/m

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5^i V/m

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- 3^i V/m

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Solution

The correct option is B $- 5^j V/m$
At point $(1, - 2)$
$E_{x} = - \frac{d V}{d x} = - (10 x + 5 y) = - 10 + 10 = 0$
$E_{y} = - \frac{d V}{d x} = - 5 x = - 5$
$∴ \to E = - 5^j V/m$

Suggest Corrections

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