Potential of the points P and Q in the circuit shown in the figure are
A
6V and −2V respectively
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6V and +2V respectively
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
−6V and −2V respectively
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−6V and +2V respectively
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A6V and −2V respectively Let i be current in the circuit Applying KVL 10−i(1)−i(3)−i(1)=0 i=105=2A As point D is earthed potential of D (VD) is zero
Potential difference across 3Ω resistor is VP−VD=i(3)=6⇒VP=6V
Potential difference across 1Ω resistor is VD−VQ=i(1)=2⇒VQ=−2V