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Capacitance of a Random Conductor

Potential of ...

Question

Potential of the points $P$ and $Q$ in the circuit shown in the figure are

A

6 V

and

- 2 V

respectively

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B

6 V

and

+ 2 V

respectively

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C

- 6 V

and

- 2 V

respectively

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D

- 6 V

and

+ 2 V

respectively

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Solution

The correct option is A $6 V$ and $- 2 V$ respectively

Let $i$ be current in the circuit
Applying KVL
$10 - i (1) - i (3) - i (1) = 0$
$i = \frac{10}{5} = 2 A$
As point D is earthed potential of D $(V_{D})$ is zero

Potential difference across $3 Ω$ resistor is $V_{P} - V_{D} = i (3) = 6 \Rightarrow V_{P} = 6 V$

Potential difference across $1 Ω$ resistor is $V_{D} - V_{Q} = i (1) = 2 \Rightarrow V_{Q} = - 2 V$

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