Question

Power dissipated in the circuit shown in the figure 30 watt . The value of R is

• A. 5 $\Omega$
• B. 15 $\Omega$
• C. 10 $\Omega$
• D. 20 $\Omega$

Answer 1

Answer: (D)

20 $\Omega$

$R_1=R_2=?$

$R_2=10\Omega ,V=15V$

and $P=30W$

Hence$,$

$p=\frac{V^2}{R_1}+\frac{V^2}{R_2}$

$\frac{{\left(10\right)}^2}{R}=30-\frac{{\left(10\right)}^2}{10}$

$\frac{100}{R}=30-10$

$R=20\Omega$

Hence,

option $\left(D\right)$ is correct answer.