wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

PQ and RS are two parallel chords of a circle whose centre is O and radius is 5 cm. If PQ = 8 cm and RS = 6 cm.The distance between PQ and RS if they lie on the same side of the centre is ___ cm

Open in App
Solution

PQ = 8cm

PL = LQ = 4cm [ the perpendicular from the centre of the circle bisects the chord]

OPL is a right angled triangle.

OL2=OP2PL2

= 5242

= 25 - 16 = 9

OL=9 = 3cm

RS = 6cm

RM = MS = 3cm

Similarly ORM is a right angled triangle.

Using Pythagoras theorem we get OM = 4 cm

LM = 4 - 3 = 1 cm

The distance between the two chords is 1 cm


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Perpendicular from the Center to a Chord Bisects the Chord
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon