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Question

PQ is a line parallel to side BC and passing through vertex A of a triangle ABC. BE || AC and CF || AB meet PQ at E and F respectively. If the base and altitude of ΔABC are 6 cm and 8 cm respectively, the area of ΔACF is ___.


A

12 cm2

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B

24 cm2

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C

48 cm2

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D

96 cm2

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Solution

The correct option is B

24 cm2


CF when drawn parallel to AB , forms parallelogram ABCF.

AC is the diagonal of the parallelogram that divides ABCF into 2 equal triangles ABC and ACF.

So, Area of ΔACF = Area of ΔABC = 12×6×8=24 cm2


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