PQ is a tangent to a circle with centre O at the point P. If triangle OPQ is an isosceles triangle, then angle OQP is equal to

30^o

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60^o

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90^o

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45^o

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Solution

The correct option is D
45^o

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Similar questions

PQ is a tangent to a circle with centre O at the point P. If $△$ OPQ is an isosceles triangle such that OP = PQ, then find the measure of $∠$ OQP.

An equilateral triangle ABC is inscribed in a circle with centre $O .$ Then, $∠ B O C$ is equal to:

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