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Question

An equilateral triangle ABC is inscribed in a circle with centre O. Then, BOC is equal to:


A

30°

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B

60°

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C

90°

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D

120°

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Solution

The correct options are
B

60°


D

120°


Given, ABC is an equilateral triangle.
BAC=60

Since, the angle subtended by a chord at the centre of a circle is twice the angle subtended by the same chord at any other point on the remaining part of the circle.
So, BOC=2×BAC=120


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