An equilateral ABC is inscribed in a circle with centre O. Then measure of $∠ B O C$ is

$30^{o}$

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$60^{o}$

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$90^{o}$

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$120^{o}$

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Solution

The correct option is D
$120^{o}$

$Δ A B C$ is an equilateral triangle inscribed in a circle with centre O.

$∴$ Measure of $∠ B O C = 2 ∠ B A C$ $= 2 \times 60^{o} = 120^{o}$

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Similar questions

An equilateral triangle ABC is inscribed in a circle with centre $O .$ Then, $∠ B O C$ is equal to:

△ A B C

∠ B O C

△ A B C

O

∠ B O C

Δ A B C

∠ B O C

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