Predict the order of Δo for the following compounds:-
(i) [Cr(H2O)6]3+
(ii) [Cr(CN)2(H2O)4]−
(iii) [Cr(CN)4(H2O)2]−
(iv) [Cr(CN)6]3−
A
Δo(i)<Δo(ii)<Δo(iii)<Δo(iv)
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B
Δo(i)>Δo(ii)>Δo(iii)>Δo(iv)
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C
Δo(ii)=Δo(iii)<Δo(i)<Δo(iv)
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D
Δo(ii)<Δo(iii)<Δo(iv)<Δo(i)
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Solution
The correct option is AΔo(i)<Δo(ii)<Δo(iii)<Δo(iv) Stronger the ligand, more is the crystal field energy. Here CN− is stronger ligand than H2O, so the appropriate order of Δo is Δo(i)<Δo(ii)<Δo(iii)<Δo(iv)