Predict the product of the following reaction.
$C H_{3} C O O H + L i A l H_{4}$

C H_{3} C H_{3}

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C H_{3} C H O

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C H_{3} C H_{2} O H

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Solution

The correct option is B $C H_{3} C H_{2} O H$
Lithium aluminium hydride reduces carboxylic acids to primary alcohols.
$C H_{3} C O O H + 4 [H] L i A l H_{4} - --- \to C H_{3} C H_{2} O H + H_{2} O$

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Similar questions

C H_{3} C = C C H_{2} C H_{3} \frac{K M n O_{4} . K O H}{373 - 383 K}

C H_{3} C O O H + C H_{3} C H_{2} O H H_{2} S O_{4} - --- \to

H_{2} O

(C H_{3})_{3} C C l + C H_{3} C O O H ⟶

C H_{3} C H_{2} O H + {C l}_{2} ⟶ C H_{3} C H O + H C l

C H_{3} C H O + {C l}_{2} ⟶ C {C l}_{3} C H O + H C l

C H_{4} + {C l}_{2} ⟶ C H_{3} C l + H C l

C H_{3} C H_{2} O H + C l_{2} \to C H_{3} C H O + H C l

C H_{3} C H O + C l_{2} \to C C l_{3} C H O + H C l

C H_{4} + C l h v - \to C H_{3} C l + H C l

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