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Question

​​present age of father is 3 more than 3 times his sons age. after 10 years father will be 10 more than twice his sons age. find their present ages

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Solution

Let the present age of son = x yrsPresent age of father = 3x + 3 yrsAFTER 10 YEARS :son's age = x + 10 yrsFather's age = 3x + 3 + 10 yrs = 3x + 13 yrsNow, according to question :3x + 13 = 2x + 10 + 103x + 13 = 2x + 20 + 103x + 13 = 2x + 303x - 2x = 30 - 13x = 17So, present age of son = 17 yrsPresent age of father = 17×3+3 = 54 yrs

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