Pressure Pr=3Fv2π2t2x
(where Pr = Pressure F = force, v = velocity, t =
time, x = distance)
State whether true or false: the above equation is dimentionally correct
A
True
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B
False
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Solution
The correct option is B False Pressure Pr=3Fv2π2t2x (where Pr = Pressure F = force, v = velocity, t =
time, x = distance)
Dimension of L.H.S = [Pr]=M1L−1T−2
Dimension
of R.H.S. = [3][F][V2][π][t2][x]=[M1L1T−2][L2T2][T2][L]=M1L2T−6
Dimension
of L.H.S. and R.H.S are not same So the relation cannot be correct
Sometimes a question is asked which is beyond our syllabus, then
certainly it must be the question of dimensional analyses