CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Pressure equation of a sound wave is P=0.02sin(3000t9x) where all quantities are in SI unit. The frequency and speed of sound wave is

A
1000π Hz, 500 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1500π Hz, 10003 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
100π Hz, 250 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200π Hz, 500 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1500π Hz, 10003 m/s
On comparing, P=0.02sin(3000t9x) with equation of travelling wave, P=Posin(ωtkx+ϕ)
We get,
Angular frequency,
ω=3000 rad/s and
wave number,
k=9 m1
Now,
Speed of sound wave,
v=ωk=30009=10003 m/s
Frequency,
f=ω2π=30002π=1500π Hz

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon