Pressure versus temperature graph of an ideal gas of equal number of moles of different volumes is plotted as shown in Figure. Choose the correct alternative?

V_{1} = V_{2}

V_{3} = V_{4}

and

V_{2} > V_{3}

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V_{1} = V_{2}

V_{3} = V_{4}

and

V_{2} < V_{3}

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V_{1} = V_{2} = V_{3} = V_{4}

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V_{4} > V_{3} > V_{2} > V_{1}

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Solution

The correct option is A $V_{1} = V_{2}$ , $V_{3} = V_{4}$ and $V_{2} > V_{3}$
According to the ideal gas law,
For a constant volume process, the Pressure-Temperature graph is a straight line.
This justifies $V_{1} = V_{2}$ and $V_{3} = V_{4}$
However, since the slope of 1-2 line is smaller than the 3-4 line, therefore, $V_{2} > V_{3}$

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