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Question
Pressure-volume (PV) work done by an ideal gaseous system at constant volume is: (where E is internal energy of the system)
Pressure-volume (PV) work done by an ideal gaseous system at constant volume is: (where E is internal energy of the system)
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Solution
The correct option is A zero
From the first law of thermodynamics,
ΔE=q+W
where,work done, (W)=−PΔV
W=−P×ΔV∵ΔV=0) since the volume is constant.
W=0
From the first law of thermodynamics,
ΔE=q+W
where,
work done, (W)=−PΔV
W=−P×ΔV∵ΔV=0) since the volume is constant.
W=0
W=−P×ΔV∵ΔV=0) since the volume is constant.
W=0
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