Question

Probability of not getting an even number when a die is thrown is :

• A. $\frac{1}{6}$
• B. $\frac{1}{4}$
• C. $\frac{1}{2}$
• D. $\frac{1}{3}$

Answer 1

Answer: (C)

$\frac{1}{2}$

the sample space has 6 possible outcomes-

$S=\{1,2,3,4,5,6\}$

Let all outcomes are equally likely(fair dice).

Hence Probability of any one outcome occurring= 1/6.

The event that we get that an even number on tossing the die can occur in 3 possible ways. Let E denote this event.

$E=\{2,4,6\}$

Now $P\left(E\right)=3\times \frac{1}{6}=\frac{1}{2}$.