Probability of solving specific problem independently by A and B are 1-2 and 1-3 respectively- If both try to solve problem independently- find the probability-

P(A)=1/2 P(B)=1/3P(AUB)=P(A)+P(B) P(A ∩ B)Since A and B are independent #160;P(A ∩ B)=P(A)*P(B)=1/6Therefore P(AUB)=1/2+1/3 1/6=2/3 ...

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Standard IX

Mathematics

Experimental/Empirical Probability

Probability o...

Question

Probability of solving specific problem independently by $A a n d B a r e \frac{1}{2} a n d \frac{1}{3}$ respectively. If both try to solve problem independently, find the probability.

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Solution

P(A)=1/2 P(B)=1/3
P(AUB)=P(A)+P(B)-P(A $\cap$ B)
Since A and B are independent P(A $\cap$ B)=P(A)*P(B)=1/6
Therefore P(AUB)=1/2+1/3-1/6=2/3

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Therefore P(AUB)=1/2+1/3-1/6=2/3