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Question

Processing times (including step times) and due dates for six jobs waiting to be processed at a work centre are given in the table. The average tardiness (in days) using the shortest processing time rule is ___ (correct two decimal places).

Job Processing time (days) Due date (days)

A 3 8

B 7 16

C 4 4

D 9 18

E 5 17

F 13 19

6.33

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Solution

The correct option is A 6.33
$By SPT Rule$

Job P.T. D.D. Job Flow Time Tardiness

A 3 8 0 + 3 = 3 0

C 4 4 3 + 4 = 7 3

E 5 17 7 + 5 = 12 0

B 7 16 12 + 7 = 19 3

D 9 18 19 + 9 = 28 10

F 13 19 28 + 13 = 41 22

Job flow time = 110 38

$Total tardiness = 38$

$Average tardiness per job$

$= \frac{Total tardiness}{No. of Jobs} = \frac{38}{6} = 6.33 d a y s$

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