Product (A) of the reaction is:

P h - N H - O | | C - P h

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P h - N H -^{18} P h

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(P h)_{2} - O H | C - N H_{2}

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P h - C H_{2} - N H - P h

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Solution

The correct option is B $P h - N H -^{18} P h$
This is Beckmann rearrangement, of oximes to give amide.
The R group trans to the leaving group $(H_{2} O)$ migrates to the nitrogen, resulting in a carbocation and the release of a water molecule.

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