Product of 6a2−7b+5ab and 2ab is a) 12a3b−14ab2+10ab b) 12a3b−14ab2+10a2b2 c) 6a2−7b+7ab d) 12a2b−7ab2+10ab
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Solution
b) 12a3b−14ab2+10a2b2 →Required product = 2ab×(6a2−7b+5ab) This is product of a trinomial by a monomial, so we multiply monomial with each term of the trinomial. ∴2ab×(6a2−7b+5ab)=2ab×6a2+2ab×(−7b)+2ab×5ab=12a3b−14ab2+10a2b2