Question

Propan$-1-$ene can be prepared from propene by treating it with:

• A. $H_{2}O$ in presence of $H_{2}S{O}_4$
• B. $Hg(OAc{)}_2$, water and subsequently with $NaB{H}_4$
• C. $H_{2}O$ in presence of $HgS{O}_4$ and $H_{2}S{O}_4$
• D. $B_2{H}_6$ in $THF$ and subsequently with $H_2{O}_2$ and $NaOH$

Answer 1

The correct option is D $B_2{H}_6$ in $THF$ and subsequently with $H_2{O}_2$ and $NaOH$

Propanol is produced by the hydroboration-oxidation reaction of propene. Propene is reacted with diborane $(B{H}_3{)}_2$ to form trialkylborane, which is oxidized to alcohol by $H_2{O}_2/aq.NaOH$.