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Dehydrohalogenation of Dihalides

Propyne is fo...

Question

Propyne is formed by heating 1,2-dibromopropane with :

A

C_{2} H_{5} O N a

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B

Alc. KOH and sodamide

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C

Aqueous

K M n O_{4}

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D

dil.

H_{2} S O_{4}

and then

K M n O_{4} / H^{+}

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Solution

The correct option is B Alc. KOH and sodamide
1,2-dibromo propane is a vicinal halide since bomine attached to adjacent carbon atoms. Vicinal dihalides on treatment with alcoholic KOH undergo dehydrohalogenation to form alkenyl halide which on treatment with sodamide gives alkyne.

1,2-dibromo propane undergoes dehydrohalogenation to give 2-bromoprop-1-ene which on on further tratment with $N a N H_{2}$ gives prop-1-yne.

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Similar questions

Q. 1,2-Dibromopropane on treatment with X moles of

N a N H_{2}

followed by treatment with

C_{2} H_{5} B r

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Q. Convert Propene to 1,2-Dibromopropane.

Q. One mole of 1,2-dibromopropane on treatment with X moles of

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1, 3

- Dibromopropane reacts with metallic zinc to form:

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Dehydrohalogenation of Dihalides

Standard XII Chemistry

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