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B
CH3−C≡CH
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C
CH3−C|Br=CH2
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D
Both B and C
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Solution
The correct option is D Both B and C The reaction will go through Markovnikov addition pathway where Br will attach to more substituted carbon and forms geminal dibromide. CH3−C≡CHHBr⟶CH3−C|Br=CH2HBr⟶CH3−Br|C|Br−CH3