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Question

Prove thatcosAsinA+1cosA+sinA1=cosecA+cotA

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Solution

cosAsinA+1cosA+sinA1

dividing in numerator & denominator with sinA
cotA1+cosecAcotAcosecA+1
now putting 1=cosec2cot2

=(cotA+cosecA)(cosec2Acot2A)(cotAcosecA+1)
=(cotA+cosecA)(cosecA+cotA)(cosecAcotA)cotAcosecA1
=(cotA+cosecA)[1cosecA+cotA)](cotAcosecA+1)
=(cotA+cosecA)

RHS Proved


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