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Question

Prove that:
cosA1+sinA+1+sinAcosA=2secA

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Solution

cosA1+sinA+1+sinAcosA

=cos2A+(1+sinA)2cosA(1+sinA)

=cos2A+1+sin2A+2sinAcosA(1+sinA)

=2+2sinAcosA(1+sinA)

=2(1+sinA)cosA(1+sinA)

=2cosA

=2secA

Hence proved.

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