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Question

Prove that cosAcosecAsinAsecAcosA+sinA=cosecAsecA

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Solution

LHS=cosAcosecAsinAsecAcosA+sinA

=cos2Asin2AsinAcosA(cosA+sinA)

=(cosAsinA)(cosA+sinA)sinAcosA(cosA+sinA)

=cosAsinAsinAcosA

=1sinA1cosA

=cosecAsecA

=RHS

Hence proved

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