Prove that- sin A - 2 sin 2 A - sin 3 A cos A - 2 cos 2 A - cos 3 A - tan 2 A

(Sin3A+SinA+2Sin2A/Cos3A+CosA+2Cos2A) =(2Sin(3A+2A/2)Cos(3A A/2)+2Sin2A/2Cos(3A+A/2)Cos(3A A/2)+2Cos2A) =(2Sin2A #10;CosA+2Sin2A/2Cos2ACosA+2Cos2 ...

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Trigonometric Ratios of Common Angles

Prove that: ...

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Prove that: $\frac{sin A + 2 sin 2 A + sin 3 A}{cos A + 2 cos 2 A + cos 3 A} = tan 2 A$

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